Milo's Math Corner

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

In a way that does make sense bcuz taking A out of a square root makes it either + or -


- how is it that im in this thread answering a math problem while im in calculus figuring out a problem....too much math >.<

yes milo that is corect lal = a AND lal = -a

any time you root the squair you will get the absolut value

no just no

Not going to make an intelligent comment, Loganatt?

why should he? you dont reply to it unless it isnt

Quote:

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Originally Posted by Milonius

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

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Question 1: It makes some sense.

Question 2: You always look stupid.

That's not very nice....

Quote:

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Originally Posted by Milonius

That's not very nice....

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You're the one with a retarded-looking sponge as an avvy.

Next math question: What is the Cosecant of an angle if the hypotenuse is 14.567 in., and the adjacent leg is 7.5 repeated (5 with a line over it) in. and the angle's measure is 35 degrees, 42 minutes, 17 seconds, and 45 hundredths of a second?
Assume that the triangle is a right triangle.


(I spent five minutes looking on my keyboard for a "Pi" button once.)

Quote:

---

Originally Posted by Milonius

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

---

A little. You are trying to 'prove' that A=-A and i think the argument you meant to make is as follows where we use the abstract complex number i defined by

i=sqrt(-1)

which implies i^2=-1

So now you write

A=sqrt(A^2)=sqrt((-A)^2)=(sqrt(-A))^2=(iA)^2=-A

thus giving the result youre trying to get. Of course this is nonsense and the flaw in the proof is as follows.

For real numbers A you have sqrt(A^2)=(sqrt(A))^2. ie you an reverse the square and square root operations. This is NOT true for the complex number i.