IMPOSSIBLE QUESTION!! Mwahaaha

[tex]

It never ever get there.

[WarChick]

I have the answer: It would take...







... a while!

Best answer yet!

[aymouna]

gloria , do you have the answer???
because if i make all the calcul ,i should be sure that your correction is righ!

[aymouna]

right (sorry)

[calt]

I'm working on it, but first let me say that the speed needed to escape the gravitational field doesn't apply here.

Escape velocity is for unpowered projectiles. Every rocket becomes an unpowered projectile when it runs out of fuel, but more on that later.

Ug=-G*M1*M1/r
Ug= potential energy of gravity (eg. your energy needs to be this big to escape)
G = Gravitational constant. _NOT 9.8M/S^2!_ that's gravitational acceleration at the surface. 6.7x10^-11 (in SI units).
M1 mass of first object (in kg)
M2 mass of second object
r distance between both object's center of mass (the center of the earth, not surface)
at the surface this comes to 11 km/s. nothing we have ever launched has moved that fast before leaving the atmosphere. Bullets don't move nearly that quickly. If that's all we had to go on then we couldn't have launched voyager or anything else.
if however you have a rocket that remains powered until r gets really really big, then it can be traveling at a velocity large enough for it's location. All rockets space probes (voyager etc) remain a powered rocket until it's moving fast enough and is far enough out that it will never return.

[wpack10]

The question is null and void as rocket cars do not exist.

[MrArchitect]

Its a trick question,
its a standard calculus question designed to fool people,
the answer is
199days 12hours 31minutes 0.280813391224seconds
as long as you always fix it after refuling is complete, it never stops moving, so its just a pure distance calculation:
300,000km at 76km/hr
+ 30,000km at 110km/hr
+ 54,000km at 95km/hr

4788.5167464114832535885167464115 hrs

[HoRde]

Dont u have to wait till durability reaches zero to repair?

[Heraclius]

Is this assuming that the car comes to a complete stop upon running out of fuel? If this is the case then it would need to stop before it runs out of fuel, because in space there is no friction so technically you only need to accelerate to 100kph and then cut the engines and you'll cruise at that speed until you hit something. Also, what is the car's acceleration upon completing refueling.

Another thing, how much fuel does it take to slow down from 100 kph to 0 kph upon reaching the moon, and if landing on it is in order, what is the acceleration due to gravity as if falls towards the moon. We already know that it is 9.8m/s/s falling towards Earth, but not many people know what the acceleration towards the moon is(this includes me).

How much does the car weigh, and does it lose weight upon refueling? If it does, it should use less fuel as it loses weight.

Is the goal for the car to reach the Moon's atmosphere or surface.

Is the car already at max speed at the beginning, or does it need to accelerate to it?


Sorry but with this many variables and assumptions I won't be able to answer the question. Could you better explain the problem?


EDIT: I am making an assumption that the car starts out in near Earth orbit rather than on the surface.

[Zenrax]

If this is the case then it would need to stop before it runs out of fuel, because in space there is no friction so technically you only need to accelerate to 100kph and then cut the engines and you'll cruise at that speed until you hit something.

Not true. Space is not empty. There are enough free ions and microscopic particles to create some friction, though it would only be noticeable at relativistic speeds.