Milo's Math Corner

[Milonius]

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

[gottibabe1]

In a way that does make sense bcuz taking A out of a square root makes it either + or -


- how is it that im in this thread answering a math problem while im in calculus figuring out a problem....too much math >.<

[CandleLite]

yes milo that is corect lal = a AND lal = -a

any time you root the squair you will get the absolut value

[Loganatt]

no just no

[Milonius]

Not going to make an intelligent comment, Loganatt?

[CandleLite]

why should he? you dont reply to it unless it isnt

[trogdor1316]

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

Question 1: It makes some sense.

Question 2: You always look stupid.

[Milonius]

That's not very nice....

[trogdor1316]

That's not very nice....

You're the one with a retarded-looking sponge as an avvy.

Next math question: What is the Cosecant of an angle if the hypotenuse is 14.567 in., and the adjacent leg is 7.5 repeated (5 with a line over it) in. and the angle's measure is 35 degrees, 42 minutes, 17 seconds, and 45 hundredths of a second?
Assume that the triangle is a right triangle.


(I spent five minutes looking on my keyboard for a "Pi" button once.)

[Wardlow]

This thread is for the discussion of anything math related. I want this to be a serious thread, so try not to go off-topic.

To start the discussion, I thought of something while sitting in Geometry today. Well, the Reflexive Property of Equality states that A = A. I thought of a way for A to not equal A! Look below:

A = √(A^2)

Think about this. Any number has two square roots: a negative and positive. Well, let's say that in this case, the A on the right side of the equal sign is negative. If you work it out, you could still get A.

A = √(-A * -A)
A = √(A^2)
A = A.

However, you could also get the result below.

A = √(-A * -A)
A = √(A^2)
A = -A

Does this make any sense at all? Is this a logical argument, or am I just making myself look stupid?

A little. You are trying to 'prove' that A=-A and i think the argument you meant to make is as follows where we use the abstract complex number i defined by

i=sqrt(-1)

which implies i^2=-1

So now you write

A=sqrt(A^2)=sqrt((-A)^2)=(sqrt(-A))^2=(iA)^2=-A

thus giving the result youre trying to get. Of course this is nonsense and the flaw in the proof is as follows.

For real numbers A you have sqrt(A^2)=(sqrt(A))^2. ie you an reverse the square and square root operations. This is NOT true for the complex number i.